F(x)=0.1x^2+10x+450

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Solution for F(x)=0.1x^2+10x+450 equation: 



(F)=0.1F^2+10F+450

We move all terms to the left:

(F)-(0.1F^2+10F+450)=0

We get rid of parentheses

-0.1F^2+F-10F-450=0

We add all the numbers together, and all the variables

-0.1F^2-9F-450=0

a = -0.1; b = -9; c = -450;
Δ = b2-4ac
Δ = -92-4·(-0.1)·(-450)
Δ = -99
Delta is less than zero, so there is no solution for the equation

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